The gas in a 250. mL piston experiences a change in pressure from 1.00 atm to 4.45 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant

56.2 mL

Explanation:

Given data

Initial volume (V₁) : 250 mL Initial pressure (P₁) : 1.00 atm Final volume (V₂) : ? Final pressure (P₂) : 4.45 atm

Assuming the gas has an ideal behavior, we can find the final volume using Boyle's law.

P₁ * V₁ = P₂ * V₂

V₂ = P₁ * V₁/P₂

V₂ = 1.00 atm * 250 mL / 4.45 atm

V₂ = 56.2 mL