Ask Question
28 July, 09:56

Apumpis used toraisethe pressure of a fluid, and it operatesby converting the mechanical shaft work to mechanicalenergyof the fluid flow. A gasoline pump is measured to consume 3.5kW ofmechanical shaftpower when operating. The diameters of the outlet and inlet of the pump are the same and the pressuredifferential between them is 7 kPa. Determine the maximum possible volumeflow rateof gas

+1
Answers (1)
  1. 28 July, 11:23
    0
    maximum possible volume flow rate = V = 0.5m^3/s

    Explanation:

    Given power consumed = 3.5kW

    pressure difference (delta - P) = 7kPa

    let maximum possible volume flow rate = V

    The rate of flow of work = W = V x Delta - P

    hence, V = W/delta P

    V = 3.5/7

    V = 0.5m^3/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Apumpis used toraisethe pressure of a fluid, and it operatesby converting the mechanical shaft work to mechanicalenergyof the fluid flow. A ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers