A student wants to make a 0.150 M aqueous solution of silver nitrate, AgNO3, and has a bottle containing 11.27 g of silver nitrate. What should be the final volume of the solution

V = 0.44 L

Explanation:

Moles is denoted by given mass divided by the molecular mass,

Hence,

n = w / m

n = moles,

w = given mass,

m = molecular mass.

From the question,

w = 11.27 g

m (for AgNO₃) = 169.87 g/mol

Hence, the moles can be calculated as -

n = w / m

n = 11.27 g / 169.87 g/mol

n = 0.066 mol

Molarity -

Molarity of a substance, is the number of moles present in a liter of solution.

M = n / V

M = molarity

V = volume of solution in liter,

From the question,

M = 0.150 M

n = 0.066 mol (calculated above)

The final volume of the solution can be calculated by using the above equation,

M = n / V

0.150 M = 0.066 mol / V

V = 0.44 L