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2 October, 22:10

Consider a general reaction

a) The ΔG° of the reaction is - 4.140 kJ mol. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25°C.)

b) What is ΔG at body temperature (37.0°C) if the concentration of A is 1.6 M and the concentration of B is 0.45 M?

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  1. 2 October, 22:19
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    a) K = 5.3175

    b) ΔG = 3.2694

    Explanation:

    a) ΔG° = - RT Ln K

    ∴ T = 25°C ≅ 298 K

    ∴ R = 8.314 E-3 KJ/K. mol

    ∴ ΔG° = - 4.140 KJ/mol

    ⇒ Ln K = - (ΔG°) / RT

    ⇒ Ln K = - (-4.140 KJ/mol) / ((8.314 E-3 KJ/K. mol) (298 K))

    ⇒ Ln K = 1.671

    ⇒ K = 5.3175

    b) A → B

    ∴ T = 37°C = 310 K

    ∴ [A] = 1.6 M

    ∴ [B] = 0.45 M

    ∴ K = [B] / [A]

    ⇒ K = (0.45 M) / (1.6 M)

    ⇒ K = 0.28125

    ⇒ Ln K = - 1.2685

    ∴ ΔG = - RT Ln K

    ⇒ ΔG = - (8.314 E-3 KJ/K. mol) (310 K) ( - 1.2685)

    ⇒ ΔG = 3.2694
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