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19 July, 08:58

If I contain 3 moles of gas in a container with a volume of 60 liters and at a

temperature of 400 K, what is the pressure inside the container? (Use mm Hg)

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Answers (2)
  1. 19 July, 10:38
    0
    P = 1246.4 mmHg

    Explanation:

    assuming ideal gas:

    PV = RTn

    ∴ R = 0.082 atm. L/K. mol

    ∴ V = 60 L

    ∴ T = 400 K

    ∴ n gas = 3 mol

    ⇒ P = RTn / V

    ⇒ P = ((0.082 atm. L/K. mol) (400 K) (3 mol)) / (60 L)

    ⇒ P = (1.64 atm) * (760 mmHg/atm)

    ⇒ P = 1246.4 mmHg
  2. 19 July, 12:12
    0
    Answer: n = 3.0 moles

    V = 60.0 L

    T = 400 K

    From PV = nRT, you can find P

    P = nRT/V = (3.0 mol) (0.0821 L-atm/K-mol) (400 K) / 60.0L

    P = 1.642 atm = 1.6 atm (to 2 significant figures)
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