Ask Question
7 March, 09:37

Calculate the empirical for the molecular formula mass and the molar mass of each of the following minerals:

(a) Limestone, CaCO3

(b) halite, NaCl

(c) beryl, Be3Al2Si6O18

(d) malachite, Cu2 (OH) 2CO3

(e) turquoise, CuAl6 (PO4) 4 (OH) 8 (H2O) 4

+3
Answers (1)
  1. 7 March, 12:19
    0
    Molar mass

    The mass present in one mole of a specific species.

    The molar mass of a compound, can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms.

    (a) Limestone, CaCO₃

    Molar mass of the atoms are -

    Calcium, Ca = 40 g / mol

    Carbon, C = 12 g/mol

    Oxygen, O = 16 g/mol

    Molecular mass of CaCO₃ = (40 g / mol) + (12 g/mol) + (3 * 16 g/mol) = 100 g/mol.

    (b) halite, NaCl

    Molar mass of the atoms are -

    Sodium, Na = 23 g/mol

    Chlorine, Cl = 35.5

    Molecular mass of NaCl = 23 + 35.5 = 58.5 g/mol.

    (c) beryl, Be₃Al₂Si₆O₁₈

    Molar mass of the atoms are -

    Beryllium, Be = 9 g/mol

    Aluminum, Al = 27 g/mol

    Silicon, Si = 28 g/mol

    Oxygen, O = 16 g/mol

    Molecular mass of Be₃Al₂Si₆O₁₈ = (3 * 9) + (2*27) + (6 * 28) + (18 * 16) = 537 g/mol.

    (d) malachite, Cu₂ (OH) ₂CO₃

    Molar mass of the atoms are -

    Copper, Cu = 63.5 g/mol

    Oxygen, O = 16 g/mol

    Carbon, C = 12 g/mol

    hydrogen, H = 1 g / mol

    Molecular mass of Cu₂ (OH) ₂CO₃ = (2 * 63.5) + (5 * 16) + (2 * 1) + (1 * 12) = 221 g/mol.

    (e) turquoise, CuAl₆ (PO₄) ₄ (OH) ₈ (H₂O) ₄

    Copper, Cu = 63.5 g/mol

    Aluminum, Al = 27 g/mol

    Phosphorous, P = 31 g/mol

    Oxygen, O = 16 g/mol

    hydrogen, H = 1 g / mol

    Molecular mass of CuAl₆ (PO₄) ₄ (OH) ₈ (H₂O) ₄ =

    (63.5*1) + (6 * 27) + (4 * 31) + (28 * 16) + (16 * 1) = 813 g/mol.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the empirical for the molecular formula mass and the molar mass of each of the following minerals: (a) Limestone, CaCO3 (b) ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers