A chemist adds 0.50L of a 0.485 M copper (II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper (II) sulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Question

Chemistry

Spanky

9 June, 12:14

A chemist adds 0.50L of a 0.485 M copper (II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper (II) sulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

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Answers (1)

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Bryce Daugherty · Answer 1

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

Number of millimoles = Molarity * Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

Number of millimoles = Molarity * Volume

= 0.485 M * 500 mL

= 242.5

Thus, we can conclude that 242.5 millimoles of copper (II) sulfate has been added by the chemist to the flask.