Determine the number of atoms and the mass of zirconium, silicon and oxygen found in 0.3384 Mol of zircon ZrSiO4, a

semiprecious Stone.

1 mol of ZrSiO₄, have, 1 mol of Zr, 1 mol of Si and 4 mol of Oxygen.

since,

1 mol of a substance have 6.022 * 10 ²³ particles,

From the question,

0.3384 mol of zircon ZrSiO₄,

hence,

from the above equation,

1 mol of a substance have 6.022 * 10 ²³ particles,

0.3384 mol = 0.3384 * 6.022 * 10 ²³ number of atoms

= 2.037 * 10 ²³ number of atoms

Hence,

0.3384 mol of ZrSiO₄ will have, 0.3384 mol of Zr, 0.3384 mol of Si and 4*0.3384 mol of Oxygen.

Hence,

number of atoms of Zr = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms number of atoms of Si = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms number of atoms of O = 4 * 0.3384 mol * 6.022 * 10 ²³ = 8.148 * 10 ²³ number of atoms

The mass is calculated as -

since,

Moles is denoted by given mass divided by the molecular mass,

Hence,

n = w / m

n = moles,

w = given mass,

m = molecular mass.

n = w / m

w = n * m

mass of Zr,

Since we know, the molecular mass of Zr = 91 g/mol

moles of Zr = 0.3384 mol

using the above formula,

w = n * m

w = 0.3384 mol * 91 g/mol = 30.79 g

hence,

The mass of Zr = 30.79 g

mass of Si,

Since we know, the molecular mass of Si = 28 g/mol

moles of Si = 0.3384 mol

using the above formula,

w = n * m

w = 0.3384 mol * 28 g/mol = 9.475 g

hence,

The mass of Si = 9.475 g

mass of O,

Since we know, the molecular mass of O = 16 g/mol

moles of Si = 1.3536 mol

using the above formula,

w = n * m

w = 1.3536 mol * 16 g/mol = 21.65 g

hence,

The mass of O = 21.65 g