The percentage yield of the following reaction is 85 %. 2 Al, + 31--> 2 AICI. How many grams of AICI, will be actually obtained from 1008 aluminium metal

Assuming the product is AlCl3

Assuming its 1008 g of metalic Al

It will yeld 4234 g of aluminium chloride.

Explanation:

Al molar mass is 26.98 g/mol, so in 1008 g of Al there is 37.36 mols of Al

The stoichometry ratio between Al and AlCl3 is 1:1, so 37.36 mols of Al would form 37.36 mols of AlCl3 if the reaction were complete, but only 85% yelds, so 1008 g of Al makes up to 0.85x37.36 mols of AlCl3 (31.76 moles)

AlCl3 molar mas is 133.33 g/mol, so 31.76 moles has 4234 g