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20 June, 20:15

How many moles of sodium hydroxide are required to react completely with 23.1 moles of sulfuric acid

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Answers (2)
  1. 20 June, 22:25
    0
    46. 2 moles of NaOH

    Explanation:

    Balanced chemical equation between sodium hydroxide and sulfuric acid

    2NaOH + H2SO4 = Na2SO4 + 2H2O

    I mole of sulphuric acid is neutralized by = 2 moles of NaOH

    23.1 mole of sulphuric acid is neutralized by = 2 x 23.1

    = 46. 2 moles of NaOH
  2. 20 June, 22:31
    0
    46.2 moles

    Explanation:

    Since 2 moles of NaOH is required to completely neutralize sulphuric acid to form a normal salt and 1 mole of sulphuric acid is required in the reaction. So if 1 mole of sulphuric acid is 23.1, then 2 moles of NaOH would be 46.2.

    A chemical balanced equation is written below

    H2SO4 + 2NaOH = Na2SO4 + 2H2O
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