For the reaction:

CH3I + Cl - → CH3Cl + I-

What is the change in enthalpy for the reaction, ΔrH, in units of kcal/mol? Provide your answer to the nearest 0.1 kcal/mol.

Hey there!

Given the reaction:

CH₃I + Cl⁻ → CH₃Cl + I⁻

Change in enthalpy for the reaction:

ΔrH = (Bond energies of breaking) - (Bond energies of formation)

Bond energy of breaking = CH₃ - I = 215 kJ/mol

Bond energy of formation = CH₃ - Cl = 330 kJ/mol

ΔrH = 215 kJ/mol - 330 kJ/mol = - 115 kJ/mol

4.184 Kj/mol = 1 Kcal/mol

-115 kJ/mol = - 115/4.184 = - 27.49 Kcal/mol