if 4.12 L of 0.85-M H3PO4 solution is be diluted to a volume of 10.00 L, what is the concentration resulting solution

The concentration resulting solution = 0.350 M

Explanation:

In case of dilution, the following formula can be used -

M₁V₁ = M₂V₂

where,

M₁ = initial concentration,

V₁ = initial volume,

M₂ = final concentration, i. e., concentration after dilution,

V₂ = final volume.

from, the question,

M₁ = 0.85 M

V₁ = 4.12 L

M₂ = ?

V₂ = 10.0 L

Using the above formula, the molarity of the final solution after dilution, can be calculated as,

M₁V₁ = M₂V₂

0.85 M * 4.12 L = M₂ * 10.0 L

M₂ = 0.85 M * 4.12 L / 10.0 L

M₂ = 0.350 M