What volume of a 0.20-M K2SO4 solution contains 57 g of K2SO4?

1.635 L

Explanation:

Molarity of a substance, is the number of moles present in a liter of solution.

M = n / V

M = molarity

V = volume of solution in liter,

n = moles of solute,

Moles is denoted by given mass divided by the molecular mass,

Hence,

n = w / m

n = moles,

w = given mass,

m = molecular mass.

From the question,

Molarity of K₂SO₄ = 0.20 M

given mass of K₂SO₄ = 57 g

Since, the molecular mass of K₂SO₄ = 174 g / mol

Using the above formula, moles can be calculated as -

n = w / m = 57 g / 174 g / mol = 0.327 mol

The volume is calculated by using the above formula,

M = n / V

V = n / M

V = 0.327 mol / 0.20 M = 1.635 L