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26 February, 06:12

Consider the hypothetical reaction 3A + 4B → C + 2D Over an interval of 2.50 s the average rate of change of the concentration of A was measured to be - 0.0560 M/s. What is the final concentration of B at the end of this same interval if its concentration was initially 1.700 M?

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  1. 26 February, 09:59
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    Final [B] = 1.665 M

    Explanation:

    3A + 4B → C + 2D

    Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt

    0.05600 M/s = 4 [B] / 2.50 s

    [B] = 0.035 M (concentration of B consumed)

    Final [B] = initial [B] - consumed [B]

    Final [B] = 1.700 M - 0.035 M

    Final [B] = 1.665 M
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