If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode? If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode?

A (aq) + 1e-→A - (aq) at the cathode and B (aq) →B + (aq) + 1e - at the anode.

A (aq) + 1e-→A - (aq) at the anode and B (aq) →B + (aq) + 1e - at the cathode

Question

Chemistry

Glenn Sparks

16 February, 21:50

If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode? If you made a voltaic cell out of this reaction, what half-reaction would be occurring at the cathode, and what half-reaction would be occurring at the anode?

A (aq) + 1e-→A - (aq) at the cathode and B (aq) →B + (aq) + 1e - at the anode.

A (aq) + 1e-→A - (aq) at the anode and B (aq) →B + (aq) + 1e - at the cathode

+1

Answers (1)

Know the Answer?

Terrence Chung · Answer 1

A (aq) + 1 e⁻ → A⁻ (aq) at the cathode and B (aq) → B⁺ (aq) + 1e⁻ at the anode.

Explanation:

In the anode occurs the oxidation, in which the reducing agent loses electrons, and its oxidation number increases.

B (aq) → B⁺ (aq) + 1e⁻

In the cathode occurs the reduction, in which the oxidizing agent gains electrons, and its oxidation number decreases.

A (aq) + 1 e⁻ → A⁻ (aq)