Ask Question
22 December, 18:29

What problem would arise if the excess acetyl‑CoA were not converted to ketone bodies?

A. Although acetyl‑CoA is not toxic, it inhibits D‑β‑hydroxyacyl‑CoA dehydrogenase.

B. Although acetyl‑CoA is not toxic, it prevents transfer of fatty acids into the mitochondria by forming acetyl carnitine.

C. Fatty acid oxidation would stop when all of the CoA is bound as acetyl‑CoA.

D. Formation of acetyl‑CoA requires uptake of a proton, and the increased pH inhibits further oxidation.

+1
Answers (2)
  1. 22 December, 20:10
    0
    C. Fatty acid oxidation would stop when all of the CoA is bound as acetyl‑CoA.

    Explanation:

    Hello,

    In this case, due to the fact that the mitochondrial pool of the CoA is short, thus, such cofactor must be recycled from acetyl-CoA through the production of ketone-like bodies. Therefore, the operation of the beta-oxidation pathway is performed, as it is necessary for energy production, in such a way one concludes that fatty acid oxidation would stop when all of the CoA is bound as acetyl‑CoA.

    Best regards.
  2. 22 December, 21:40
    0
    The correct answer is C fatty acid oxidation would stop when all of the CoA is bound as acetyl CoA.

    Explanation:

    Acetyl CoA is the principle end product of beta oxidation of even chain fatty acid such as palmitic acid.

    When the cellelar label of actyl CoA increases at that time the excess acetyl CoA is converted to ketone bodies by the process called ketogenesis.

    According to the question if the excess acetyl CoA is not converted to ketone bodies then it will interfere with the oxidation of fatty acid because fatty acid molecules will not get any CoA SH molecule to activate themselves to initiate a new round of beta oxidation.

    As a result fatty acid oxidation will stop.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What problem would arise if the excess acetyl‑CoA were not converted to ketone bodies? A. Although acetyl‑CoA is not toxic, it inhibits ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers