What volume of a 0.750 M solution of hydrochloric acid a solution of HCL can be prepared from the HCL produced by the reaction of 25.0 of NaCl with an excess of sulphuric acid?

NaCl + H2SO4? HCl + NaHSO4

0.570 L

Explanation:

Given:

Concentration of the HCl solution = 0.750 M

Mass of NaCl in the reaction = 25.0

Number of moles of NaCl in the reaction = Mass of NaCl / Molar mass of NaCl

also,

Molar mass of NaCl = 22.98 + 35.45 = 58.43 grams

thus,

Number of moles of NaCl in the reaction = 25 / 58.43 = 0.4278 moles

now,

1 mol of NaCl reacts to form 1 mol of HCl

thus,

0.4278 moles of NaCl reacts to form 0.4278 mol of HCl

also,

Concentration = Moles / volume of solution

0.750 = 0.4278 / volume of solution

or

volume of solution = 0.570 L