A gas has a volume of 3L at 21'c, if the gas heater to 100'c, what is the new volume?

38.1 L

Explanation:

Data given:

initial volume V1 of a gas = 3 L

initial Temperature T1 of a gas = 21 °C

convert Temperature to Kelvin

T1 = °C + 273

T1 = 21°C + 273 = 294 K

final Temperature T2 of a gas = 100°C

convert Temperature to Kelvin

T2 = °C + 273

T2 = 100°C + 273 = 373 K

final Volume V2 of a gas = ?

Solution:

This problem will be solved by using Charles' law equation at constant pressure.

The formula used

V1 / T1 = V2 / T2

As we have to find out Volume, so rearrange the above equation

V2 = V1 x T2 / T1

Put value from the data given

V2 = 3 L x 373 K / 294 K

V2 = 38.1 L

So the final Volume of a gas = 38.1 L