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25 January, 12:17

When 50.0 g of 0.200 M NaCl at 24.1 C is added to 100.0 g M AgNO3 at 24.1 C in calorimeter, the temperature increases to 25.0 C as AgCl2 forms. Assuming the specific heat of solution and products is 4.20J/gC, calculate the approximate amount of heat in joules produced.

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  1. 25 January, 13:19
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    567 J

    Explanation:

    Mass of NaCl = 50 grams

    Mass of AgNO₃ added = 100.0 grams

    Change in temperature, ΔT = (25°C - 24.1°C) = 0.9° C

    Mass of the solution, m = 100 + 50 = 150 grams

    Specific heat of the solution, C = 4.20 J/gC

    now,

    the heat released = mCΔT

    on substituting the respective values, we get

    The heat released = 150 * 4.20 * 0.9 = 567 J
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