Consider the solubilities of a particular solute at two different temperatures.

Temperature (°C) Solubility (g/100 gH2O)

20.0 44.0

30.0 80.9

1. Suppose a saturated solution of this solute was made using 60.0 gH 2 O at 20.0°C. How much more solute can be added if the temperature is increased to 30.0°C?

We can still add 22.2 g of the solute

Explanation:

A saturated solution means that there is as much solute in the solution as its solubility allows.

First we calculate the mass of the solute present in a saturated solution with 60.0 g H₂O at 20.0°C:

60.0 gH₂O * 44 gSolute/100 gH₂O = 26.4 g solute

The ratio of the solubilities at 20 °C and 30 °C is

80.9/44.0 = 1.84

This means that there can be 1.84 times more solute when the temperature is 30 °C.

26.4 g solute * 1.84 = 48.6 g

So the mass of the solute that we can still add is:

48.6 - 26.4 = 22.2 g