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10 August, 01:27

Identify the precipitate or lack thereof for the following:CaCl2 (aq) + K2CO3 (aq) - -> CaCO3 + 2KClA) CaCO3B) KClC) No precipitateFeCl2 (aq) + (NH4) 2SO4 (aq) - -> FeSO4 + 2NH4ClA) FeSO4B) NH4ClC) No precipitate

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  1. 10 August, 01:54
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    A) CaCO₃

    C) No precipitate

    Explanation:

    To answer these questions we need to consider the solubility rules.

    Identify the precipitate or lack thereof for the following:

    CaCl₂ (aq) + K₂CO₃ (aq) ⇒ CaCO₃ (s) + 2 KCl (aq)

    Group II carbonates are insoluble. Thus, CaCO₃ is insoluble. Salts containing Group I cations are soluble. Thus, KCl is soluble.

    FeCl₂ (aq) + (NH₄) ₂SO₄ (aq) ⇒ FeSO₄ (aq) + 2 NH₄Cl (aq)

    Most sulfates are soluble. Thus, FeSO₄ is soluble. Salts containing the ammonium ion are soluble. Thus, NH₄Cl is soluble.
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