How many grams of BrCl form when 239.7g Cl2 react with excess Br2

Mass = 1568.9 g

Explanation:

Given dа ta:

Mass of Cl₂ = 239.7 g

Mass of BrCl form = ?

Solution;

Chemical equation;

Cl₂ + Br₂ → 2BrCl

Number of moles of Cl₂:

Number of moles = mass / molar mass

Number of moles = 239.7 g / 35.5 g/mol

Number of moles = 6.8 mol

Now we will compare the moles of Cl₂ and BrCl.

Cl₂ : BrCl

1 : 2

6.8 : 2*6.8 mol = 13.6 mol

Mass of BrCl:

Mass = number of moles * molar mass

Mass = 13.6 mol * 115.357 g/mol

Mass = 1568.9 g