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31 January, 04:57

The enthalpy of combustion of hard coal averages - 35 kJ/g, that of gasoline, 1.28 x 105 kJ/gal. How many kilograms of hard coal provide the same amount of hat as is available from 1.0 gallon gasoline? Assume that the density of gasoline is 0.692 g/mL (the same s density of isooctane).

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  1. 31 January, 08:50
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    3.657 kg

    Explanation:

    Given:

    Enthalpy of combustion of hard coal = - 35 kJ/g

    Enthalpy of combustion of gasoline = 1.28 * 10⁵ kJ/gal

    Density of gasoline = 0.692 g/mL

    now,

    The heat provide 1 gallon of gasoline provide = 1.28 * 10⁵ kJ

    and,

    heat provided by the 1 gram of coal = 35 kJ

    or

    1 kJ of heat is provided by (1/35) gram of hard coal

    therefore,

    For 1.28 * 10⁵ kJ of heat, mass of hard coal = 1.28 * 10⁵ kJ * (1 / 35)

    or

    For 1.28 * 10⁵ kJ of heat, mass of hard coal = 3657.14 grams = 3.657 kg
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