To what Celsius temperature must 67.0 mL of krypton gas at 18.0°C be changed so the volume will triple? Assume the pressure and the amount of gas are held constant. Enter your answer to four significant figures.

Question

Chemistry

Blondie

Yesterday, 23:17

To what Celsius temperature must 67.0 mL of krypton gas at 18.0°C be changed so the volume will triple? Assume the pressure and the amount of gas are held constant. Enter your answer to four significant figures.

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Answers (1)

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Alayna Johnston · Answer 1

Answer: 600°C

Explanation:

This reaction is explained by Charles' law as the pressure is constant.

From the question, we obtained:

V1 = 67mL

T1 = 18°C = 18 + 273 = 291K

V2 = 3V1 (Vol is tripled) = 3x67 = 201mL

T2 = ?

Applying the Charles' law,

V1 / T1 = V2 / T2

67/291 = 201 / T2

Cross multiply to express in linear form.

67xT2 = 291x201

Divide both side by 67, we have:

T2 = (291x201) / 67

T2 = 873K

Converting to Celsius temperature, we have

T°C = K - 273

T°C = 873 - 273 = 600°C