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28 February, 19:53

how much of a 25 mg/ml chloramphenicol stock solution do we need to make 400 ml of growth media taht has final 25 ug/ml concentration of chloramphenicol

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  1. 28 February, 20:56
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    Answer: 0.4mL of the stock solution is needed

    Explanation:

    This is simply a dilution analysis. From the question, the following were obtained:

    C1 = 25 mg/mL = 25x10^-3g/mL

    V1 = ?

    C2 = 25 ug/mL = 25x10^-6g/mL

    V2 = 400ml

    Applying the dilution formula, we have:

    C1V1 = C2V2

    25x10^-3 x V1 = 25x10^-6 x 400

    Divide both side by 25x10^-3, we have:

    V1 = (25x10^-6 x 400) / 25x10^-3

    V1 = 0.4mL

    Therefore, 0.4mL of the stock solution need.
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