Ask Question
3 November, 14:27

What is the molarity of a potassium triiodide solution, KI3 (aq), if 30.00 mL of the solution is required to completely react with 25.00 mL of a 0.500 M thiosulfate solution, K2S2O3 (aq)

+1
Answers (1)
  1. 3 November, 17:17
    0
    The molarity is 0.203 M

    Explanation:

    Using the formula C (oxi) x V (oxi) / [C (red) x V (red) ] = N (oxi) / N (red)

    Where oxi and red means reducing agent and oxidising agent respectively.

    C = Concentration, V = Volume and N = number of moles.

    C (oxi) = 0.5 M

    V (oxi) = mL

    C (red) = ?

    V (red) = 30mL

    Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI

    so N (red) = 1, N (oxi) = 2

    from the equation above,

    C (red) = 0.5 x 25 x 1 / (2 x 30)

    = 0.203 M.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the molarity of a potassium triiodide solution, KI3 (aq), if 30.00 mL of the solution is required to completely react with 25.00 mL ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers