Ask Question
6 November, 11:46

26.6 mL of 2.50 M stock solution of sucrose is diluted to 50.0 mL. A 16.0 mL sample of the resulting solution is then diluted to 45.0 mL. A 20.0 mL sample of this solution is then diluted to 75.0 mL. What is the concentration of sucrose in the final solution?

+1
Answers (1)
  1. 6 November, 14:03
    0
    In the final solution, the concentration of sucrose is 0.126 M

    Explanation:

    Hi there!

    The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:

    Ci · Vi = Cf · Vf

    Where:

    Ci = concentration of the original solution

    Vi = volume of the solution taken to prepare the more diluted solution.

    Cf = concentration of the more diluted solution.

    Vf = volume of the more diluted solution.

    For the first dillution:

    26.6 ml · 2.50 M = 50.0 ml · Cf

    Cf = 26.6 ml · 2.50 M / 50.0 ml

    Cf = 1.33 M

    For the second dilution:

    16.0 ml · 1.33 M = 45.0 ml · Cf

    Cf = 16.0 ml · 1.33 M / 45.0 ml

    Cf = 0.473 M

    For the third dilution:

    20.0 ml · 0.473 M = 75.0 ml · Cf

    Cf = 20.0 ml · 0.473 M / 75.0 ml

    Cf = 0.126 M

    In the final solution, the concentration of sucrose is 0.126 M
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “26.6 mL of 2.50 M stock solution of sucrose is diluted to 50.0 mL. A 16.0 mL sample of the resulting solution is then diluted to 45.0 mL. A ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers