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28 February, 14:23

If a 2.8 mole sample of gas initially occupies 54 L at 3.8 atm, what is its temperature in K?

n=

R=

T=

+5
Answers (1)
  1. 28 February, 16:06
    0
    Answer: 893.7K

    Explanation:

    From the question, we obtained the following:

    V = 54L

    n = 2.8moles

    P = 3.8 atm

    R = 0.082atm. L/mol / K

    T = ?

    Applying the ideal gas equation, we have:

    PV = nRT

    T = PV / nR

    T = (3.8x54) / (2.8x0.082)

    T = 893.7K
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