The student is now told that the four solids, in no particular order, are barium chloride (BaCl2BaCl2), sugar (C6H12O6C6H12O6), benzoic acid (C6H5COOHC6H5COOH), and potassium bromide (KBrKBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 MM solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.

Question

Chemistry

Misael

10 February, 09:16

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2BaCl2), sugar (C6H12O6C6H12O6), benzoic acid (C6H5COOHC6H5COOH), and potassium bromide (KBrKBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 MM solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.

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Yair Faulkner · Answer 1

The concept applied is the conductivity as it relates to the dissociation and the number of ions in solution. BaCl2 and KBr are ionic solids that will dissociate completely in water to give trivalent and divalent ions respectively.

Benzoic acid on the other hand is a weak acid as such it will not dissociate in water. sugar is a covalent compound.

Hence BaCl2 will have the highest conductivity based on the aforementioned reasons, then followed by KBr; BaCl2 > KBr > C6H5COOH > C6H12O6