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14 November, 08:26

What is the volume (in cm^ 3) of 1.2 moles of water vapor at RTP? Calculate the mass of this water vapor.

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  1. 14 November, 08:59
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    Volume = 29400 cm³

    Mass = 21.6 g

    Explanation:

    Given dа ta:

    Number of moles of water vapors = 1.2 mol

    Mass of water vapor = ?

    Volume of water vapors = ?

    Solution:

    Room temperature = 25 °C (25+273 = 298 K)

    Room pressure = 1 atm

    PV = nRT

    V = nRT/P

    V = 1.2 mol * 0.0821 atm. K⁻¹. mol⁻¹. L * 298 K / 1 atm

    V = 29.4 L

    In cm³:

    29.4 * 1000 = 29400 mL

    mL = cm³

    Mass of water vapors:

    Mass = number of moles * molar mass

    Mass = 1.2 mol * 18 g/mol

    Mass = 21.6 g
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