Ask Question
17 July, 09:08

Iodine, I2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. What is the temperature (in K) in a 71.4 mL bulb that contains 0.276 g of I2 vapor at a pressure of 0.478 atm?

+3
Answers (1)
  1. 17 July, 09:52
    0
    382.63 K

    Explanation:

    We are given;

    Volume of Iodine as 71.4 mL Mass of Iodine as 0.276 g Pressure of Iodine as 0.478 atm

    We are required to calculate the temperature of Iodine

    We are going to use the ideal gas equation; According to the ideal gas equation; PV = nRT, where R is the ideal gas constant, 0.082057 L. atm/mol. K. Rearranging the formula;

    T = PV : nR

    But, n, the number of moles = Mass : Molar mass

    Molar mass of iodine = 253.8089 g/mol

    Thus, n = 0.276 g : 253.8089 g/mol

    = 0.001087 moles

    Therefore;

    T = (0.478 atm * 0.0714 L) : (0.001087 moles * 0.082057)

    = 382.63 K

    Thus, the temperature of Iodine in Kelvin is 382.63 K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Iodine, I2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. What is the temperature (in K) in a ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers