Express the equilibrium constant for the following reaction. P (g) + 3/2 Cl2 (g) ↔ PCl3 (g) K = [PCl3]^2/[P]^2[Cl2]^3K = [PCl3]/[P][Cl2]^3/2K = [P][Cl2]^3/2/[PCl3]K = [P]^1/2[Cl2]^1/3/[PCl3]^1/2K = [PCl3]^2/[P]2[Cl2]3

Question

Chemistry

Zechariah

20 November, 13:47

Express the equilibrium constant for the following reaction. P (g) + 3/2 Cl2 (g) ↔ PCl3 (g) K = [PCl3]^2/[P]^2[Cl2]^3K = [PCl3]/[P][Cl2]^3/2K = [P][Cl2]^3/2/[PCl3]K = [P]^1/2[Cl2]^1/3/[PCl3]^1/2K = [PCl3]^2/[P]2[Cl2]3

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Answers (2)

Know the Answer?

Louis Barrett · Answer 1

b) K = [PCl3] / [P][Cl2]∧ (3/2)

Explanation:

P (g) + 3/2 Cl2 (g) ↔ PCl3 (g)

equlibrium constant (K):

⇒ K = [PCl3] / [P].[Cl2]∧ (3/2)

Cristal Chase · Answer 2

K = [PCl3]/[Cl2]^3/2[P]

Explanation:

To get an expression for the equilibrium constant, we simply place the concentrations of both the reactants and the product in terms of square bracket and raise them to the power of their coefficients in the balanced equations.

After doing this we place the expression of the product over that of the reactant.

K = [PCl3]/[Cl2]^3/2[P]