How many milliliters of 10.0 M HCl (aq) are needed to prepare 790.0 mL of 1.00 M HCl (aq)

Question

Chemistry

Harper Horn

14 December, 09:19

How many milliliters of 10.0 M HCl (aq) are needed to prepare 790.0 mL of 1.00 M HCl (aq)

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Answers (1)

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Landen Hutchinson · Answer 1

79.0 mL

Explanation:

Given data

Initial concentration (C₁) : 10.0 M Initial volume (V₁) : ? Final concentration (C₂) : 1.00 M Final volume (V₂) : 790.0 mL

In order to find the volume required of the concentrated solution, we will use the dilution rule.

C₁ * V₁ = C₂ * V₂

V₁ = C₂ * V₂/C₁

V₁ = 1.00 M * 790.0 mL/10.0 M

V₁ = 79.0 mL