If 325 g of ammonia is used, what amount, in moles, of nitrogen monoxide will be produced in the

following equation: 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g) ?

19.12 moles of NO will produced.

Explanation:

Given dа ta:

Mass of ammonia = 325 g

Moles of NO produced = ?

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Number of moles of Ammonia:

Number of moles = mass / molar mass

Number of moles = 325 g / 17 g/mol

Number of moles = 19.12 mol

Now we will compare the moles of ammonia and NO.

NH₃ : NO

4 : 4

19.12 : 19.12

Thus 19.12 moles of NO will produced.