The molarity of a 4.200 L solution is 1.230 M Na2CO3. What is the mass of Na2CO3

within the solution?

547.5g

Explanation:

To get the mass, you need moles.

moles = (molarity) (Liters)

moles = (1.230M) (4.200L) = 5.166 moles Na2CO3

Now, just use stoichiometry

molar mass of Na2CO3 = 2 (mass of Na) + (mass of C) + 3 (mass of O)

= 2 (22.9) + 12.01 + 3 (16) = 105.99g/mol

5.166moles (105.99g/mol)

= 547.544

But, the measurements given had 4 significant figures, so in chemistry we write:

547.5g