Ask Question
4 June, 12:04

For the reaction

2

AgNO

3

+

Na

2

CrO

4



Ag

2

CrO

4

+2

NaNO

3

2AgNO3+Na2CrO4⟶Ag2CrO4+2NaNO3

how many grams of sodium chromate, Na2CrO4, are needed to react completely with

12.1

12.1

g of silver nitrate, AgNO3?

+3
Answers (1)
  1. 4 June, 12:24
    0
    Mass of Na₂CrO₄ = 5.75 g

    Explanation:

    First of all we will write the balance chemical equation.

    2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃

    Now we will calculate the moles of AgNO₃.

    Number of moles = mass / molar mass

    Molar mass of AgNO₃ = 107.87 + 14 + 3 * 16 = 169.87 g/mol

    Number of moles = mass / molar mass

    Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol

    Now we will compare the moles of AgNO₃ and Na₂CrO₄ from balance chemical equation.

    AgNO₃ : Na₂CrO₄

    2 : 1

    0.071 : 1/2 * 0.071 = 0.0355

    Now we will calculate the mass of Na₂CrO₄.

    Molar mass of Na₂CrO₄ = 23*2 + 52 + 16*4 = 162 g/mol

    Mass of Na₂CrO₄ = number of moles * molar mass

    Mass of Na₂CrO₄ = 0.0355 mol * 162 g/mol

    Mass of Na₂CrO₄ = 5.75 g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “For the reaction 2 AgNO 3 + Na 2 CrO 4 ⟶ Ag 2 CrO 4 +2 NaNO 3 2AgNO3+Na2CrO4⟶Ag2CrO4+2NaNO3 how many grams of sodium chromate, Na2CrO4, are ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers