What is the specific heat of a piece of tin if it measures 36.0g and is heated from 18.0 degrees Celsius. It must absorb 678 j of heat to reach this temperature?

The answer to your question is C = 1.046 J/g°C

Explanation:

Data

Specific heat = ?

mass = 36 g

ΔT = 18°C

Q = 678 J

To calculate the specific heat, use the formula of heat and solve it for C

Formula

Q = mCΔT

Solve for C

C = Q / mΔT

Substitution

C = 678 / (36 x 18)

Simplification

C = 678 / 648

Result

C = 1.046 J/g°C