What volume does 4.24g of argon gas occupy at 58.2 degrees celcuis and 1528torr

V = 1.434 L

Explanation:

Given dа ta:

Mass of argon = 4.24 g

Temperature = 58.2 °C

Pressure = 1528 torr

Volume = ?

Solution:

58.2 °C = 58.2 + 273 = 331.2 K

1528/760 = 2.01 atm

Number of moles:

Number of moles = mass/molar mass

Number of moles = 4.24 g / 39.948 g/mol

Number of moles = 0.106 mol

Volume:

PV = nRT

V = nRT/P

V = 0.106 mol * 0.0821. atm. L. mol⁻¹. K⁻¹ * 331.2K / 2.01 atm

V = 2.88 atm L / 2.01 atm

V = 1.434 L