1. How many Nitrogen atoms are there in 4.58 mole of N. O.?

Answer: 1.29 x 10^24 atoms of Nitrogen is present

Explanation:

molar mass of NO = 14 + 16 = 30g/mol

number of moles of NO = 4.58mol

number of moles of Nitrogen in NO is = (14/30) x4.58 = 2.1373 moles

To get the number of atoms of Nitrogen we use Avogadro's number

Number of atoms of Nitrogen = mole fraction of Nitrogen x Avogadro's constant = 2.1373 x 6.02 x 10^23 = 1.29 x 10^24 atoms