1.00mol of oxygen gas has a pressure of 2.50atm at 325K. Use the ideal gas law to determine the volume of the gas.

10.66L

Explanation:

The following were obtained from the question:

n = 1 mole

P = 2.5atm

T = 325K

R = 0.082atm. L/Kmol

V = ?

Using the ideal gas equation PV = nRT, the volume of the gas can easily be obtain as illustrated below:

PV = nRT

V = nRT/P

V = (1 x 0.082 x 325) / 2.5

V = 10.66L

The volume of the gas is 10.66L