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23 July, 13:19

What mass of Al2O3 (alumina, a finely divided white powder that is produced as billows of white smoke) is formed in the reaction of 2800 kg of aluminum?

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  1. 23 July, 16:11
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    5290.7 kg of Al₂O₃ are produced in the reaction of 2800 kg of Al

    Explanation:

    The reaction to produce alumina is:

    4 Al + 3O₂ → 2 Al₂O₃

    So, let's convert the mass of Al to moles (mass / molar mass)

    2800 kg = 2800000 g (Then, 2.8 * 10⁶ g)

    2.8 * 10⁶ g / 26.98 g/mol = 103780.5 moles of Al

    Ratio is 4:2, so with the moles I have, I will produce the half of moles of alumina.

    103780.5 mol / 2 = 51890.25 moles of Al₂O₃

    Now we can convert these moles to mass (molar mass. mol)

    101.96 g/mol. 51890.25 mol = 5290729.8 g

    5290729.8 g → 5290.7 kg
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