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13 May, 21:04

If the pressure exerted by a gas at 0.00 °C in a volume of 0.0010 L of 5.00 atm, how many moles of gas are present?

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  1. 13 May, 23:57
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    2.23 x 10^-4 mol

    Explanation:

    0°C = 273 K

    PV = nRT

    n = PV/RT

    n = (5.00 atm * 0.0010 L) / (0.0821 * 273 K)

    n = 2.23 x 10^-4
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