You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with KOH (aq) according to the following balanced chemical equation:?

HA + KOH → KA + H₂O

Explanation:

The unknown solid acid in water can release its proton as this:

HA + H₂O → H₃O⁺ + A⁻

As we have the anion A⁻, when it bonded to the cation K⁺, salt can be generated, so the reaction of HA and KOH must be a neutralization one, where you form water and a salt

HA + KOH → KA + H₂O

It is a neutralization reaction because H⁺ from the acid and OH⁻ from the base can be neutralized as water