A.) How many moles of ethyl alcohol are produced by reaction of 4.2 mol of ethyl acetate? N=?

b.) How many grams of ethyl alcohol are produced by reaction of 4.2 mol of ethyl acetate with H2? N=?

c.) How many grams of ethyl alcohol are produced by reaction of 16.0 g of ethyl acetate with H2? N=?

D.) How many grams of H2 are needed to react with 16.0 g of ethyl acetate? N=?

a) 8.4 moles ethyl alcohol

b) 387 grams ethyl alcohol

c) 16.77 grams ethyl alcohol

d) 0.735 grams H2

Explanation:

Step 1: Data given

Molar mass of ethyl acetate = 88.11 g/mol (C4H8O2)

Molar mass of ethyl alcohol = 46.07 g/mol (C2H6O)

Step 2: The balanced equation

C4H8O2 + 2H2 → 2C2H6O

Step 3: How many moles of ethyl alcohol are produced by reaction of 4.2 mol of ethyl acetate?

For 1 mol mol ethyl acetate we need 2 moles H2 to produce 2 moles ethyl alcohol.

For 4.2 mol of ethyl acetate we'll have 2*4.2 = 8.4 moles ethyl alcohol

Step 4: How many grams of ethyl alcohol are produced by reaction of 4.2 mol of ethyl acetate with H2?

Mass of ethyl alcohol = moles * molar mass

Mass ethyl alcohol = 8.4 moles * 46.07 g/mol

Mass ethyl alcohol = 387 grams

Step 5: How many grams of ethyl alcohol are produced by reaction of 16.0 g of ethyl acetate with H2?

Moles ethyl acetate = 16.0 grams / 88.11 g/mol = 0.182 moles

Moles ethyl alcohol = 2*0.182 = 0.364 moles

Mass ethyl alcohol = 16.77 grams

Step 6: How many grams of H2 are needed to react with 16.0 g of ethyl acetate?

For 0.182 moles ethyl acetate we need 2*0.182 = 0.364 moles H2

0.364 moles H2 = 0.364 * 2/02 g/mol = 0.735 grams H2