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14 July, 12:33

A chemist makes a solution of Ca (NO3) 2 by dissolving 21.3 g Ca (NO3) 2 in water to make 100.0 mL of solution. What is the concentration of NO3 - ions in the solution? Assume that Ca (NO3) 2 is the only solute in the solution. The molar mass of Ca (NO3) 2 is 164.10 g/mol.

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  1. 14 July, 12:51
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    [NO₃⁻ ] = 2.596 M

    Explanation:

    Ca (NO₃) ₂ dissolves in water according to the following equation:

    Ca (NO₃) ₂ ⇒ Ca²⁺ + 2NO₃⁻

    The moles of Ca (NO₃) ₂ that dissolve is found as followed:

    (21.3 g) / (164.10 g/mol) = 0.1298 ... mol

    The number of NO₃⁻ ions are related to the above quantity by the molar ratio:

    (0.1298 mol Ca (NO₃) ₂) (2NO₃⁻/Ca (NO₃) ₂) = 0.2596 ... mol NO₃⁻

    The concentration of the nitrate ions is then calculated:

    [NO₃⁻ ] = (0.2596 ... mol) / (100.0ml) x (1000mL/L) = 2.596 M
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