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17 November, 12:27

When 2.246 grams of a calcium chloride hydrate was heated, 0.728 grams of water were

released. Determine the formula of the hydrate

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Answers (1)
  1. 17 November, 15:06
    0
    CaCl₂. 3H₂O

    Explanation:

    We are given;

    Mass of calcium chloride hydrate as 2.246 g Mass of water of crystallization as 0.728 g

    We are required to determine the formula of the hydrate;

    First; we determine the mass of the anhydrous salt

    Mass of anhydrous Calcium chloride = Mass of hydrate - mass of water

    = 2.246 g - 0.728 g

    = 1.518 g

    Second; determine the moles of anhydrous salt and water

    Moles = mass : molar mass

    Moles of anhydrous salt

    Molar mass of CaCl₂ = 110.98 g/mol

    Moles of CaCl₂ = 1.518 g : 110.98 g/mol

    = 0.0137 moles

    Moles of water

    Molar mass of water = 18.02 g/mol

    Moles of water = 0.728 g : 18.02 g/mol

    = 0.0404 moles

    Third; we determine the whole number mole ratio of anhydrous salt to water

    CaCl₂ : H₂O

    0.0137 moles : 0.0404 moles

    0.0137/0.0137 : 0.0404/0.0137

    1 : 2.95

    1 : 3

    Therefore, the formula of the hydrate is CaCl₂. 3H₂O
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