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21 December, 04:32

The molecular weight of calcium carbonate, CaCO3, is 100.09 3.

mol

How many moles of calcium carbonate are in 63.8 g of calcium carbonate?

Express the answer using 3 significant figures.

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Answers (1)
  1. 21 December, 05:04
    0
    Number of Moles = Reacting mass / Molecular mass

    = 63.8 / 100.09

    = 0.637g

    Hence, the moles of calcium carbonate in 63.8 g of calcium carbonate is 0.637g
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