Determine the number of grams of hcl that can react with 0.750 g of Al (OH) 3 according to the following reaction Al (OH) ₃ (s) + 3HCl (aq) →AlCl₃ (aq) + 3H₂O (aq)

Question

Chemistry

Cullen Bishop

16 December, 08:58

Determine the number of grams of hcl that can react with 0.750 g of Al (OH) 3 according to the following reaction Al (OH) ₃ (s) + 3HCl (aq) →AlCl₃ (aq) + 3H₂O (aq)

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Answers (1)

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Evangeline Chandler · Answer 1

1040 g HCl

Explanation:

Al (OH) ₃ + 3HCl = > AlCl₃ + 3H₂O

moles Al (OH) ₃ = 750g/78g·mol⁻¹ = 9.62 mol

moles HCl used = 3 x moles Al (OH) ₃ consumed = 3 (9.62) mol HCl = 1038.46 g. ≈ 1040 g HCl (3 sig. figs.)