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31 May, 07:30

A student lost part of his lab notebook and didn't know what the original measure should have been. He knows that he calculated a 35.5% error and his experimental measurement was 15.6 cm. What are the two possible values for the actual measurement?

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  1. 31 May, 10:39
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    21.1cm or 10.1cm

    Explanation:

    Since the percent error is 35.5% and the experimental measurement was 15.6cm, the two possible values for the actual measurement are 15.6 plus 35.5% of 15.6 or 15.6 minus 35.5% of 15.6.

    This is this:

    15.6 + (0.355 x 15.6)

    = 15.6 + 5.54

    = 21.1cm

    Or this:

    15.6 - (0.355 x 15.6)

    = 15.6 - 5.54

    = 10.1cm
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