A monolayer containing 3.19 * 10 - 6 g of oleic acid has an area of 20.0 cm 2. The density of oleic acid is 0.895 g / mL. What is the thickness of the monolayer (the length of an oleic acid molecule) ?

1.78 * 10⁻⁷ cm

Explanation:

Using,

Density = Mass / Volume

Given:

Area = 20.0 cm²

Density = 0.895 g/mL

Mass = 3.19 * 10⁻⁶ g

Applying in the density formula as:

0.895 g/mL = 3.19 * 10⁻⁶ g / Volume (ml)

Volume = 3.56 * 10⁻⁶ mL

Since, 1 mL = cm³

So, Volume = 3.56 * 10⁻⁶ cm³

Thickness (height) of monolayer = ?

Also, Volume = area x thickness

So,

Thickness = Volume/Area = 3.56 * 10⁻⁶ cm³ / 20.0 cm² = 1.78 * 10⁻⁷ cm